8x^2+59x+64=-x-8

Solution for 8x^2+59x+64=-x-8 equation:

8x^2+59x+64=-x-8

We move all terms to the left:

8x^2+59x+64-(-x-8)=0

We add all the numbers together, and all the variables

8x^2+59x-(-1x-8)+64=0

We get rid of parentheses

8x^2+59x+1x+8+64=0

We add all the numbers together, and all the variables

8x^2+60x+72=0

a = 8; b = 60; c = +72;
Δ = b2-4ac
Δ = 602-4·8·72
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-36}{2*8}=\frac{-96}{16}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+36}{2*8}=\frac{-24}{16}
=-1+1/2
$